The reaction of benzoic acid with methanol in | vedclass

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(B) The reaction is an acid-catalyzed Fischer esterification.In this mechanism,the carboxylic acid $(RCOOH)$ loses an $-OH$ group,and the alcohol $(R'

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$C_6H_5CO^{18}OCH_3 + H_2O$

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(B) The reaction is an acid-catalyzed Fischer esterification.In this mechanism,the carboxylic acid $(RCOOH)$ loses an $-OH$ group,and the alcohol $(R'OH)$ loses an $-H$ atom to form water $(H_2O)$.The oxygen atom of the alcohol is incorporated into the ester linkage.Given the reaction: $C_6H_5COOH + CH_3O^{18}H \xrightarrow{H^+} C_6H_5CO^{18}OCH_3 + H_2O$.The oxygen isotope $^{18}O$ from the methanol ends up in the ester product $(C_6H_5CO^{18}OCH_3)$,and the water molecule formed contains the oxygen from the carboxylic acid group.

The reaction of benzoic acid with methanol in the presence of an acid catalyst $(H^+)$ is shown below. Identify the correct product.
$C_6H_5COOH + CH_3O^{18}H \xrightarrow{H^+} \text{Product}$

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The reaction of benzoic acid with methanol in the presence of an acid catalyst $(H^+)$ is shown below. Identify the correct product.$C_6H_5COOH + CH_3O^{18}H \xrightarrow{H^+} \text{Product}$